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In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IB when β=50.(a) 0.01mA(b) 0.25mA(c) 0.03mA(d) 0.02mAI have been asked this question in an internship interview.The doubt is from The Common Emitter Configuration in section Transistor Characteristics of Electronic Devices & Circuits |
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Answer» CORRECT ANSWER is (d) 0.02mA The BEST EXPLANATION: IC=V ACROSS RL/RL=5V/5KΩ=1mA. IB=IC/β=1/50=0.02mA. |
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