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In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mAA. 2 mAB. 4 mAC. 6 mAD. 8 mA |
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Answer» Correct Answer - B `alpha=0.95 = I_C/I_E` and `I_E=I_C-I_B " " therefore I_C=I_E+I_B` `therefore I_C=0.95 I_E` Thus `I_E+I_B=0.95I_E` `therefore I_E(1-0.95) = -I_B` `therefore I_E(5/100)=2/10 mA ` (-ve sign neglected) `50I_E=200 " " therefore I_E=4mA` |
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