1.

In ΔPQR measure of angle Q is 90°. If cotP = 8/15, and PQ = 4 cm, then what is the length (in cm) of side PR?1). 8.52). 7.53). 54). 4

Answer»

In ΔPQR measure of ANGLE Q is 90°,

COT P = Base/Perpendicalar

⇒ Cot P = PQ/QR

⇒ PQ/QR = 8/15

⇒ 4/QR = 8/15

⇒ QR = 7.5

By pythagoras Theorem,

PR2 = PQ2 + QR2

⇒ PR2 = 42 + 7.52

⇒ PR2 = 16 + 56.25 = 72.25

∴ PR = 8.5 cm


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