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In ΔPQR measure of angle Q is 90°. If cotP = 8/15, and PQ = 4 cm, then what is the length (in cm) of side PR?1). 8.52). 7.53). 54). 4 |
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Answer» In ΔPQR measure of ANGLE Q is 90°, COT P = Base/Perpendicalar ⇒ Cot P = PQ/QR ⇒ PQ/QR = 8/15 ⇒ 4/QR = 8/15 ⇒ QR = 7.5 By pythagoras Theorem, PR2 = PQ2 + QR2 ⇒ PR2 = 42 + 7.52 ⇒ PR2 = 16 + 56.25 = 72.25 ∴ PR = 8.5 cm |
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