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In every 45 minutes, the number of nuclei of a radionuclides becomes 80 % of its number before 45 minutes, then the time (in minute) in which the number of nuclei of that nuclide becomes 64% of its initial number isA. 50B. 100C. 90D. 40 |
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Answer» Correct Answer - C Radioactive disintegration follow `I^(st)` order kinetics `lambda =(l)/(t) ln .(N_(0))/(N_(t)) " " (1)/(45) ln .(100)/(80) =(1)/(t) ln (100)/(64)` `t=45 ((2 ln 10 -6 ln 2)/(ln 10 -3 ln 2))=90` |
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