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    				| 1. | In Fig. switch `S` is closed for a long time. At `t = 0`, if it is opened, then A. total heat produced in resistor `R` after opening the switch is `(1)/(2) (Lepsilon)/(R^(2))`B. total heat produced in resistor `R_(1)` after opening the switch is `(1)/(2) (Lepsilon^(2))/(R^(2)) ((R_(1))/(R_(1) + R_(2)))`C. heat produced in resistor `R_(1)` after opening the switch is `(1)/(2) (R_(2)L epsilon^(2))/((R_(1) + R_(2)) R^(2))`D. no heat will be produced in `R_(1)` | 
| Answer» Correct Answer - C Just before opening the switch, the current in the inductor is `(E)/(R )*` Energy stored in it `= (1)/(2) L((epsilon)/(R ))^(2)` This energy will dissipate in resistance `R_(1)` and `R_(2)` in the ratio `(1)/(R_(1))` and `(1)/(R_(2))*` | |