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In Fig, the bar is uniform and weighing `500 N`. How large must `W` be if `T_(1)` and `T_(2)` are to be equal? A. `500N`B. `300N`C. `750N`D. `1500N` |
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Answer» Correct Answer - D Taking torque about the attachmet point for `W` get `-T_(1)(0.4L)+T_(2)(0.3L)+500(0.2L)=0` `T=1000N`, were `T_(1)=T_(2)=T` `SigmaF_(y)=0gt2T-W-500=0` `implies W=1500N` |
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