In Half-wave controlled rectifier calculate the average value of the current for 2.5 Ω resistive load if the supply is sin(5.2t) and firing angle is 26°.(a) 0.8 V(b) 0.15 V(c) 0.12 V(d) 0.21 VThe question was posed to me in my homework.I would like to ask this question from Solid-State Switching Circuits in division Introduction to Solid-State Switching Circuits of Electric Drives

In Half-wave controlled rectifier calculate the average value of the c

1.	In Half-wave controlled rectifier calculate the average value of the current for 2.5 Ω resistive load if the supply is sin(5.2t) and firing angle is 26°.(a) 0.8 V(b) 0.15 V(c) 0.12 V(d) 0.21 VThe question was posed to me in my homework.I would like to ask this question from Solid-State Switching Circuits in division Introduction to Solid-State Switching Circuits of Electric Drives
Answer» RIGHT option is (C) 0.12 V Best explanation: In Half-wave controlled rectifier, the average VALUE of the current is Vm(1+cos(∝))÷2πR=(1+cos(26°))÷6.28×2.5=.12 V. The THYRISTOR will conduct from ∝ to π.

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