In -I effect, which position is most active?(a) Ortho(b) Para(c) Meta(d) All are equally activeI had been asked this question by my college professor while I was bunking the class.This intriguing question comes from Aromatic Nitration in portion Nitration of Unit Processes

In -I effect, which position is most active?(a) Ortho(b) Para(c) Meta(

1.	In -I effect, which position is most active?(a) Ortho(b) Para(c) Meta(d) All are equally activeI had been asked this question by my college professor while I was bunking the class.This intriguing question comes from Aromatic Nitration in portion Nitration of Unit Processes
Answer» The correct option is (c) META For explanation I would say: -I effect reduces the REACTIVITY of all the positions in the ring, and the effect being GREATER at ortho and PARA positions, hence meta is more active.

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