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In magnesium sulphide, the ratio by mass of Mg and S is 3:4. What is the ratio of number of Mg and S atoms?

Answer»

SOLUTION :FORMULA of MAGNESIUM sulphide=MgS
Ratio by mass of Mg and S=3:4
No. of atoms in 3g of Mg=`(N_(A))/(24)xx3=(N_(A))/(8)`
`"No. of atoms in 4g of S"=(N_(A))/(32)xx4=(N_(A))/(8)`
`therefore "Ratio fo number of Mg and S"=(N_(A))/(8):(N_(A))/(8) or 1:1`


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