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In OR gate for 13 numbers of inputs what are the stages possible for it?(a) 1239(b) 213(c) 13(d) 1387I got this question at a job interview.Origin of the question is Boolean Algebra in chapter Boolean Algebra and Modeling Computations of Discrete Mathematics

Answer»

Right choice is (B) 213

Easiest explanation: OR gate works in a WAY such that if any of the INPUT is BINARY low(or 0), the output of the gate is binary 1(or high). Here, the NUMBER of stage possible = 2^n = 2^13.



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