In previous question, what would be the apparent wavelengths in front of and behind the locomotive if a wind of speed `10 m//s` were blowing in the same direction as that in which the locomotive is travelling?A. `0.65 m, 0.73 m`B. `0.60 m, 0.73 m`C. `0.65 m, 0.78 m`D. `0.60 m, 0.71 m`

In previous question, what would be the apparent wavelengths in front

1.	In previous question, what would be the apparent wavelengths in front of and behind the locomotive if a wind of speed `10 m//s` were blowing in the same direction as that in which the locomotive is travelling?A. `0.65 m, 0.73 m`B. `0.60 m, 0.73 m`C. `0.65 m, 0.78 m`D. `0.60 m, 0.71 m`
Answer» Correct Answer - C `f_(1) = f ((v+w)/(v+w-v_(s)))` `= 546.15 Hz` `lambda_(1) = (v+w)/(f_(1)) = (355)/(5+6.15) = 0.65 m` `f_(2) = f ((v+w)/(v+w+v_(s)))=500 ((345+10)/(345+10+30))=461 Hz` `lambda_(2)=(v+w)/f_(2)=(345+10)/461=0.77 m`

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In previous question, what would be the apparent wavelengths in front of and behind the locomotive if a wind of speed `10 m//s` were blowing in the same direction as that in which the locomotive is travelling?A. `0.65 m, 0.73 m`B. `0.60 m, 0.73 m`C. `0.65 m, 0.78 m`D. `0.60 m, 0.71 m`

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