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In Q.94, time for which the car decelerates is:A. `(alpha)/(alpha + beta)t`B. `(beta)/(alpha + beta) t`C. `(alpha)/(beta) t`D. `(beta)/(alpha)t` |
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Answer» Correct Answer - A `t_(1) = (v_(m))/(alpha) = ((beta)/(alpha + beta))t` |
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