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In single phase RLE load, calculate the Peak inverse voltage using the data: (Vs)r.m.s=89 V, f=50 Hz,E=440 V.(a) 521.2 V(b) 527.8 V(c) 597 V(d) 529 VThe question was posed to me during an interview.I'd like to ask this question from Solid-State Switching Circuits topic in division Introduction to Solid-State Switching Circuits of Electric Drives

Answer»

Right choice is (c) 597 V

Easy explanation: In a SINGLE PHASE, RLE load the peak INVERSE VOLTAGE across the thyristor VT=Vm+E=529 V.



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