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In sinθ = cos(θ - 45°), where θ and θ - 45° are acute angles, find the degree measure of θ. |
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Answer» sinθ = cos(θ - 45°) ⇒ cos(90° - θ) = cos(θ - 45°) ⇒ 90° - θ = θ - 45° ⇒ 2θ = 135° ⇒ θ =\(\frac{135°}{2} = 67(\frac{1}{2})°\) |
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