1.

In the above question, change in internal energy of gas is

Answer»

`-2660.23J`
`-2777.23 J`
`-2767.23 J`
`-2600 J`

SOLUTION :CHANGE in internal energy `DeltaU=nC_vDeltaT, n ` No of moles `C_v=R/(gamma-1):.DeltaU=(NR)/(gamma-1)DeltaT`
`DeltaU=(2xx8.31xx(189-300))/(5/3-1)=-2767.23J`


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