In the adjoining figure, seg AC and seg BD intersect each other in poi

1.	In the adjoining figure, seg AC and seg BD intersect each other in point P and AP/CP = BP/DP Prove that, ∆ABP ~ ∆CDP
Answer» Proof: In ∆ABP and ∆CDP, AP/CP = BP/DP [Given] ∠APB ≅ ∠CPD [Vertically opposite angles] ∴ ∆ABP ~ ∆CDP [SAS test of similarity]

In the adjoining figure, seg AC and seg BD intersect each other in point P and AP/CP = BP/DP Prove that, ∆ABP ~ ∆CDP

Answer»

Proof:

In ∆ABP and ∆CDP,

AP/CP = BP/DP [Given]

∠APB ≅ ∠CPD [Vertically opposite angles]

∴ ∆ABP ~ ∆CDP [SAS test of similarity]

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In the adjoining figure, seg AC and seg BD intersect each other in point P and AP/CP = BP/DP Prove that, ∆ABP ~ ∆CDP

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