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In the Arrhenius for a certain reaction, the value of `A` and `E_(a)` (activation energy) are `4 xx 10^(13) sec^(-1)` and `98.6 "kJ mol"^(-1)`, respectively. If the reaction is of first order, the temperature at which its half-life period is `10` minutes isA. `280 K`B. `290 K`C. `311.35 K`D. `418.26 K` |
Answer» Correct Answer - C Calculation of `k`: We know that `k = (2.303)/(t) "log"((a)/(a-x))` `(t_(1//2)=10xx60 sec)=1.1558xx10^(-3)` According to Arrehenius equation, `log k = log A - (Ea)/(2.303 RT)` Substituting the various values in the above equation `log 1.155 xx 10^(-3) = log 4 xx 10^(13) - (98.6)/(2.303 xx 8.314 xx 10^(-3) xx T)` On usual calculation, `T = 311.35 K` |
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