In the calculations the horizontal airborne distance is assumed to be much greater than 35 feet.(a) True(b) FalseI have been asked this question in a national level competition.My doubt is from Estimation of Take-off Distances topic in chapter Take-off and Landing Performance of Aircraft Performance

In the calculations the horizontal airborne distance is assumed to be

1.	In the calculations the horizontal airborne distance is assumed to be much greater than 35 feet.(a) True(b) FalseI have been asked this question in a national level competition.My doubt is from Estimation of Take-off Distances topic in chapter Take-off and Landing Performance of Aircraft Performance
Answer» The correct choice is (a) True The BEST explanation: In the calculations the horizontal airborne DISTANCE is assumed to be much greater than 35 feet. The airborne distance is given by SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) where W is weight D is drag G is acceleration DUE to gravity V is velocity FN is NORMAL force.

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