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In the `CB` mode of a transistor, when the collector voltage is changed by `0.5` volt. The collector current changes by `0.05 mA`. The output resistance will beA. `10k Omega`B. `20k Omega`C. `5k Omega`D. `2.5k Omega` |
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Answer» Correct Answer - A Here, `DeltaV_(c)=0.5V and DeltaI_(C)=0.05 mA=0.05 xx 10^(-3)A` Output resistance is given by, `R_("out") =(DeltaV_(C))/(DeltaI_(C))=(0.5)/(0.05xx10^(-3))` `=10^(4)Omega=10Omega` |
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