1.

In the `CB` mode of a transistor, when the collector voltage is changed by `0.5` volt. The collector current changes by `0.05 mA`. The output resistance will beA. `10k Omega`B. `20k Omega`C. `5k Omega`D. `2.5k Omega`

Answer» Correct Answer - A
Here, `DeltaV_(c)=0.5V and DeltaI_(C)=0.05 mA=0.05 xx 10^(-3)A`
Output resistance is given by,
`R_("out") =(DeltaV_(C))/(DeltaI_(C))=(0.5)/(0.05xx10^(-3))`
`=10^(4)Omega=10Omega`


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