In the circuit diagram given below, three resistors R_(1),R_(2) and R_(3) of 5Omega,10Omega and 20Omega respectively are cooncted as shown. (A) Current through each resistor (B) Total current in the circuit (c )Total resistance in the circuit

In the circuit diagram given below, three resistors R_(1),R_(2) and R_

1.	In the circuit diagram given below, three resistors R_(1),R_(2) and R_(3) of 5Omega,10Omega and 20Omega respectively are cooncted as shown. (A) Current through each resistor (B) Total current in the circuit (c )Total resistance in the circuit
Answer» Solution :SINCE the resistors are connected in parallel, the potential difference ACROSS each resistor is same (i.e. V=10V) Therefore, the current through `R_(1)` is `I_(1)=(V)/(R_(1))=(10)/(5)=2A` Current through `R_(2)=I_(2)=(V)/(R_(2))=(10)/(10)=1A` Current through `R_(3)=I_(3)=(V)/(R)(10)/(20)=0.5A` (B) Total current in the circuit, `I=I_(1)+I_(2)+I_(3)` `=2+1+0.5=3.5A` (C) Total resistance in the circuit `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))` `=(1)/(5)+(1)/(10)+(1)/(20)` `=(4+2+1)/(20)` `(1)/(R_(p))=(7)/(20)` Hence, `R_(p)=(20)/(7)=2.857Omega`