InterviewSolution
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InterviewSolution
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In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second. The heat generated in the 4 ohms resistor isA. `1 Cals^(-1)`B. `2 Cals^(-1)`C. `3 Cals^(-1)`D. `4 Cals^(-1)` |
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Answer» Correct Answer - B Let current is `5 Omega` resistors be `I_(1)` and `in 4 Omega` resistors be `I_(2)`, then `I_(2)//I_(1) = (1//2)`. The heat generated in the ` 5 Omega` resistor is `10 cals^(-1)` Given `I_(1)^(2) xx 5 = 10 or (( 2 I ^(2))^(2) xx 5 = 10 or I_(2)^(2) = (1)/(2)`. Heat in the `4 Omega` resistor will be `(I_(2)^(2))^(2) xx 4 = 2 cal s^(-1)`. |
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