1.

In the circuit shown in figure the current flowing through 5 Ω resistance is :​

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Req= 10×25/(10+25)

=50/7

Using V=iReq

V=2.1×50/7= 15 volt

Now at 5 ohm

V=iR

i=v/R=15/25=0.6

Current at 5 ohm RESISTANCE is 0.6 ampere



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