1.

in the cirmuit given beiiow, lind the camem through 100bog302+15

Answer»

let the voltage at the centre be V

and current in 10Ω = i1 , 20Ω = i2 and 30Ω = i3

let i1 = i2+i3

so, according to Kirchoff rules

=> (10-v)/10 = (v-15)/30 + (v-6)/20=> 10-v = v/3 -5 +v/2 -3=> 11v/6 = 18=> v = 108/11

so, Ii = (10-108/11)/10 = 2/110 = 1/55 A



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