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In the diagram shown in figure, match the following columns (take `g=10 ms^(-2)`) `{:("Column I","Column II"),("(A) Normal reaction","(p) 12 SI unit"),("(B) Force of friction","(q) 20 SI unit"),("(C) Acceleration of block","(r) zero"),(,"(s) 2 SI unit"):}` |
Answer» Correct Answer - A`rarr`q,B`rarr`p,C`rarr`s `N=mg-20sqrt(2) sin 45^(@) =20N` `f mu_(k)N=12N` Since, `20sqrt(2) cos 45^(@) gt muN` block will move and kinetic friction will act, `a=(20sqrt(2) cos 45^(@)-mu_(k)N)/(m)=(20-12)/(4)=2 ms^(-2)` |
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