In the fig. mass M 10 g. is placed on an inclinedplane. In order to ke

1.	In the fig. mass M 10 g. is placed on an inclinedplane. In order to keep it at rest, the value of massm will be:(2) 10 3 g(1) 5 g(3) 0.10 gThe mechanical advantage of a wheel axle i(4) 3 9
Answer» For the mass M to be kept at rest the net force should be 0 so, mg = Mgsin∅ = 1010sin(30)=> m = 1010(1/2)/g = 10/2 = 5gm. option 1

In the fig. mass M 10 g. is placed on an inclinedplane. In order to keep it at rest, the value of massm will be:(2) 10 3 g(1) 5 g(3) 0.10 gThe mechanical advantage of a wheel axle i(4) 3 9

Answer»

For the mass M to be kept at rest the net force should be 0

so, mg = Mgsin∅ = 10*10*sin(30)=> m = 10*10*(1/2)/g = 10/2 = 5gm.

option 1

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In the fig. mass M 10 g. is placed on an inclinedplane. In order to keep it at rest, the value of massm will be:(2) 10 3 g(1) 5 g(3) 0.10 gThe mechanical advantage of a wheel axle i(4) 3 9

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