1.

In the figure below, ∠DEC+∠BFC is equal to _______ .(A) ∠ BCD – ∠ BAD(B) ∠ BAD + ∠ BCF(C) ∠ BAD + ∠ BCD(D) ∠ CBA + ∠ ADC

Answer»


Discussion

No Comment Found

Related InterviewSolutions