1.

In the figure, seg AB || Y-axis and seg CB || X-axis. Co-ordinates of points A and C are given. To find AC, fill in the boxes given below.

Answer»

In ∆ABC, ∠B = 900

∴ (AB)2 + (BC)2 = [(Ac)2 …(i) … [Pythagoras theorem]

seg CB || X-axis 

∴ y co-ordinate of B = 2 

seg BA || Y-axis 

∴ x co-ordinate of B = 2 

∴ co-ordinate of B is (2, 2) = (x1, y1

co-ordinate of A is (2, 3) = (x2, y2

Since, AB || to Y-axis, 

d(A, B) = Y2 – Y1 

d(A,B) = 3 – 2 = 1 

co-ordinate of C is (-2, 2) = (x1, y1

co-ordinate of B is (2, 2) = (x2, y2

Since, BC || to X-axis, 

d(B, C) = x2 – x1 

d(B,C) = 2 – -2 = 4 

∴ AC2 = 12 + 42 …[From (i)] 

= 1 + 16 = 17 

∴ AC = √17 units …[Taking square root of both sides].



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