1.

In the figure, set aC and seg BD intersect each other in point P and `(AP)/(CP)=(BP)/(DP)`. Prove that `DeltaABP~DeltaCDP`.

Answer» In `Delta` and `DeltaCDP`
`(AP)/(CP)=(BP)/(DP)`……(Given)
`/_APB~=/_CPD`……..(Vertically opposite angles)
`:.DeltaABP~DeltaCDP` …….(SAS test similarity)


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