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In the figure, set aC and seg BD intersect each other in point P and `(AP)/(CP)=(BP)/(DP)`. Prove that `DeltaABP~DeltaCDP`. |
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Answer» In `Delta` and `DeltaCDP` `(AP)/(CP)=(BP)/(DP)`……(Given) `/_APB~=/_CPD`……..(Vertically opposite angles) `:.DeltaABP~DeltaCDP` …….(SAS test similarity) |
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