In the figure shown, find. (a) time of flight of the projectile along the inclined plane. (b) range OP.

In the figure shown, find. (a) time of flight of the projectile along

1.	In the figure shown, find. (a) time of flight of the projectile along the inclined plane. (b) range OP.
Answer» Correct Answer - A::B (a) Horizontal component of initial velocity, `u_x = 20(sqrt2) cos 45^@ = 20 m//s` Vertical component of initial velocity `u_y = 20(sqrt2) sin 45^@ = 20 m//s` Let the particle strikes at P after time t, then horizontal displacement `OQ = u_xt = 20t ` In vertical displacement, `u_yt` or 20t is upwards and `1/2 g t^2` or `5t^2` is downwards. But net displacement is upwards, therefore 20 t should be greater than `5t^2` and `QP = 20t - 5t^2 ` In `Delta OPQ, ` `tan 37^@ = (QP/OQ)` or, ` 3/4 = ((20t - 5t^2)/(20t))` Solving this equation, we get `t = 1s` (b) Range `OP = OQ sec 37^@` ` =(20t)(5/4)` Substituting t = 1s, we have OP = 25m .

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In the figure shown, find. (a) time of flight of the projectile along the inclined plane. (b) range OP.

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