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In the figure shown, find acceleration of the system and tenslons `T_(1),T_(2) and T_(3) (Take = 10 m//s^(2))` |
Answer» `a = ("Net pulling force")/("Total mass")` `= ((3 + 4 - 2 - 1)g)/(3 + 4 + 2 + 1) = 4m//s^(2)` `4kg` `40 - T_(1) = 4a :. T_(1) = 24N` `3kg` `T_(1) + 30 - T_(2) = 3a :. T_(2) = 42N` `1kg` `T_(3) - 10 = (1) (a) :. T_(3) = 14N` |
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