In the first 10s of a body’s motion, the velocity changes from 10 m/s to 20m/s. During the next 30s the velocity changes from 20m/s to 50m/s. What is the average acceleration in m/s^2?(a) 1(b) 2(c) 3(d) 0.5This question was addressed to me during an online interview.I'm obligated to ask this question of Kinematic Equations for Uniformly Accelerated Motion in portion Motion in a Straight Line of Physics – Class 11

In the first 10s of a body’s motion, the velocity changes from 10 m/

1.	In the first 10s of a body’s motion, the velocity changes from 10 m/s to 20m/s. During the next 30s the velocity changes from 20m/s to 50m/s. What is the average acceleration in m/s^2?(a) 1(b) 2(c) 3(d) 0.5This question was addressed to me during an online interview.I'm obligated to ask this question of Kinematic Equations for Uniformly Accelerated Motion in portion Motion in a Straight Line of Physics – Class 11
Answer» CORRECT choice is (a) 1 To explain I would SAY: Average acceleration is the total change in velocity by the total change in time. Here, total change in velocity = 50-10 = 40m/s, and total change in time = 30+10 =40S. THEREFORE, average acceleration = 1 m/s^2.

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