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In the first order reaction, half of the reaction is completed in 100 seconds. The time for `99%` of the reaction to occur will beA. 664.64sB. 646.6sC. 660.9sD. 654.5 s |
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Answer» Correct Answer - A a) `k=0.693/100 s^(-1)` `t(99.9%) = 2.303/k log a/(a-x)` `=(2.303 xx 100s/(0.693)) xx log 100/1` `=(2.303 xx 100 xx 2)/(0.693) = 666.64` s |
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