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In the following circuit, the value of Norton’s resistance between terminals a and b are ___________(a) RN = 1800 Ω(b) RN = 270 Ω(c) RN = 90 Ω(d) RN = 90 ΩI had been asked this question by my school principal while I was bunking the class.This intriguing question originated from Norton’s Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory |
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Answer» RIGHT option is (d) RN = 90 Ω Explanation: By writing loop equations for the circuit, we get, VS = VX, IS = IX VS = 600(I1 – I2) + 300(I1 – I2) + 900 I1 = (600+300+900) I1 – 600I2 – 300I3 = 1800I1 – 600I2 – 300I3 I1 = IS, I2 = 0.3 VS I3 = 3IS + 0.2VS VS = 1800IS – 600(0.01VS) – 300(3IS + 0.01VS) = 1800IS – 6VS – 900IS – 3VS 10VS = 900IS For VOLTAGE, VS = RN IS + VOC Here VOC = 0 So, Resistance RN = 90Ω. |
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