1.

In the following circuit, the value of Norton’s resistance between terminals a and b are ___________(a) RN = 1800 Ω(b) RN = 270 Ω(c) RN = 90 Ω(d) RN = 90 ΩI had been asked this question by my school principal while I was bunking the class.This intriguing question originated from Norton’s Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory

Answer» RIGHT option is (d) RN = 90 Ω

Explanation: By writing loop equations for the circuit, we get,

VS = VX, IS = IX

VS = 600(I1 – I2) + 300(I1 – I2) + 900 I1

= (600+300+900) I1 – 600I2 – 300I3

= 1800I1 – 600I2 – 300I3

I1 = IS, I2 = 0.3 VS

I3 = 3IS + 0.2VS

VS = 1800IS – 600(0.01VS) – 300(3IS + 0.01VS)

= 1800IS – 6VS – 900IS – 3VS

10VS = 900IS

For VOLTAGE, VS = RN IS + VOC

Here VOC = 0

So, Resistance RN = 90Ω.


Discussion

No Comment Found

Related InterviewSolutions