1.

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be A. 10 mVB. 0.1 VC. 1.0 VD. 10 V

Answer» Correct Answer - C
`(V_(0))/(V_("in"))=beta(R_(i))/(R_("in"))rArrV_(0)=beta(R_(i))/(R_("in"))xxV_("in")=100xx(10kOmega)/(1kOmega)xx1mV=1V`


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