InterviewSolution
Saved Bookmarks
| 1. |
In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be A. 10 mVB. 0.1 VC. 1.0 VD. 10 V |
|
Answer» Correct Answer - C `(V_(0))/(V_("in"))=beta(R_(i))/(R_("in"))rArrV_(0)=beta(R_(i))/(R_("in"))xxV_("in")=100xx(10kOmega)/(1kOmega)xx1mV=1V` |
|