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In the following process, `H_(2)(g) to 2H(g), " "Delta_(H-H)H^(ө)=435.0" kJ "mol^(-1)` the enthalpy change involved is theA. bond dissociation enthalpy of H-H bondB. bond association enthalpy of H-H bondC. mean bond dissociation enthalpy of H-H bondD. mean bond association enthalpy of H-H bond |
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Answer» Correct Answer - A In the given equation, `H_(2)(g) to 2H(g),Delta_(H-H)H^(ө)=435.0kJ" "mol^(-1)` the enthalpy change involved is the bond dissociation enthalpy of H-H bond. |
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