1.

In the given circuitRc= 3 kohm, VCE = 6 V and VBE= 0.7 V.If B = 50, the base resistor Rb will be (1) 7.5 x 104 32(3) 4.5 * 1052(2) 5 x 1042(4) 1.125 105 22​

Answer»

Answer:

Resistance of base resistor is GIVEN as

R_b = 1.75 \times 10^4 ohm

Explanation:

As we know that voltage GAIN in COMMON EMITTER transistor is given as

\frac{v_{CE}}{v_{BE}} = \frac{i_c R_c}{i_b R_b}

also we know that CURRENT gain in this transistor is given as

\beta = \frac{i_c}{i_b}

\beta = 50

\frac{v_{CE}}{v_{BE}} = \frac{3000}{R_b} \times 50

\frac{6}{0.7} = \frac{150000}{R_b}

R_b = 1.75 \times 10^4 ohm

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Topic : Transistor

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