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In the given figure, a 15 m/s2 represents the totalacceleration of a particle moving in the clockwisedirection in a circle of radius R - 2.5 m at a giveninstant of time. The speed of the particle is :-Ya(1) 5.7 m/s(2) 6.2 m/s(3) 4.5 m/s(4) 5.0 m/s |
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Answer» ac = v^2 / R 15 cos 30° = V^2 / 2.5 V^2 = 32.73 V = 5.7 m/sec. |
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