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In the given figure, ABCD is a trapezium such that `AL bot DC and BM bot DC`. If AB = 7 cm, BC = AD = 5 cm and AL = BM = 4 cm then ar(trap. ABCD) = ? A. `24 cm^(2)`B. `40 cm^(2)`C. `55 cm^(2)`D. `27.5 cm^(2)` |
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Answer» Correct Answer - B `CM^(2)=BC^(2)-BM^(2)=(5)^(2)-(4)^(2)=9 rArrCM=3 cm.` Similarly, DL = 3 cm. `therefore CD = DL + LM + CM =(3+7+3)cm = 13 cm.` ar(trap. ABCD) `=[(1)/(2)xx(7+13)xx4]cm^(2)=40 cm^(2)`. |
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