1.

In the given graph the activation energy , `E_(a)` for the reverse reaction will be A. 150 kJB. 50 kJC. 200 kJD. 100 kJ

Answer» Correct Answer - b
`DeltaH = E_(a) f = E_(a) b`
`100 = 150-E_(b)`
`E_(a) b = 50 `kJ .


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