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In the masses of A and B are 10 kg and 5 kg . Calculate the minimum mass of C which may stop A from slipping Coefficient of static friction between block A and table is 0.2 . |
Answer» Here , ` m_(A) = 10 kg , m_(B) = 5 kg `, `m_(C) = ? , mu = 0 . 2 ` To avoid slipping of A force of friction = T wt . Of B ` mu (m_(C) + m_(A)) g = m_(B) g` `0 .2 (m + 10 ) = 5 , m + 10 = (5) /(0.2) = 25 ` `m =25 - 10 = 15 kg` . |
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