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In the nuclear chain ractio: `._(92)^(235)U + ._(0)^(1)n rarr ._(56)^(141) Ba + ._(36)^(92)Kr + 3 ._(0)^(1)n + E` The number fo neutrons and energy relaesed in nth step is:A. `3n, nE`B. `3^(n), nE`C. `3^(n), 3^(n-1) E`D. none of these |
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Answer» Correct Answer - `(c)` In `n^(th)` step neutrons ejected will be `3^(n)` and energy `3^(n-1)E` because one step ejects 3 electrons and energy `E.e.g` consider `II` step. In `2nd` step a neutrons `(3^(2))` and `3E` energy `(3^(2-1)E)` is liberated. |
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