In the previous question, in place of disc a ring is used whose inner radius is `R_(1)` and outer radius is `R_(2)` Now how much extra weight should be added on the other side, so that the ring can just come out of water ?

In the previous question, in place of disc a ring is used whose inner

1.	In the previous question, in place of disc a ring is used whose inner radius is `R_(1)` and outer radius is `R_(2)` Now how much extra weight should be added on the other side, so that the ring can just come out of water ?
Answer» Surface tension force on the disc is `(T)2pi(R_(1)+R_(2))` For balance `(T)2pi(R_(1) + R_(2)) = (Deltam)g rArr ((T)2pi(R_(1)) - R_(2))/(g)`

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In the previous question, in place of disc a ring is used whose inner radius is `R_(1)` and outer radius is `R_(2)` Now how much extra weight should be added on the other side, so that the ring can just come out of water ?

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