In the problem "up" is taken positiveA ball is thrown vertically upwar

1.	In the problem "up" is taken positiveA ball is thrown vertically upward with an initial velocity 19.6m/s after 5s has a velocity of
Answer» Explanation: Max HEIGHT attained by it is Hmax = u^2 = 19.6 × 19.6 ÷ 2 × 9.8 2g Hmax = 19.6m PUTTING the VALUE in 3rd EQ. of motion v^2 - u^2 = 2as v^2 = 19.6 × 19.6 + 2 × 9.8 × 19.6 v^2 = 384.16 + 384.16 v^2 = 768.32 v = 27.71 m/s or 28 m/s I HOPE IT WILL HELP YOU PLEASE MARK IT BRAINLY ♥

In the problem "up" is taken positiveA ball is thrown vertically upward with an initial velocity 19.6m/s after 5s has a velocity of

Answer»

Explanation:

Max HEIGHT attained by it is

Hmax = u^2 = 19.6 × 19.6 ÷ 2 × 9.8

Hmax = 19.6m

PUTTING the VALUE in 3rd EQ. of motion

v^2 - u^2 = 2as

v^2 = 19.6 × 19.6 + 2 × 9.8 × 19.6

v^2 = 384.16 + 384.16

v^2 = 768.32

v = 27.71 m/s or 28 m/s

I HOPE IT WILL HELP YOU

PLEASE MARK IT BRAINLY ♥

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In the problem "up" is taken positiveA ball is thrown vertically upward with an initial velocity 19.6m/s after 5s has a velocity of

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