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In the Q.23, the angle of projection with the horizontal is:-A. `tan^(-1)((4)/(5))`B. `tan^(-1)((5)/(4))`C. `tan^(-1)((5)/(8))`D. `tan^(-1)((8)/(5))` |
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Answer» Correct Answer - C `because u_(x)=40` and `u_(y)=25` `therefore tan theta=(u_(y))/(u_(x))=(25)/(40)=(5)/(8)` |
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