1.

In the question number 82, the maximum permissible speed to avoid slipping isA. `18.6"ms"^(-1)`B. `28.6"ms"^(-1)`C. `38.6"ms"^(-1)`D. `48.6"ms"^(-1)`

Answer» Correct Answer - C
The maximum permissible speed is given by `v("max")=sqrt((Rg+(mu+tan theta))/(1-mutantheta))=sqrt((300xx10xx(0.2+0.27))/(1-0.2xx0.27))`
`=38.6ms ^(-1)`


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