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In the question number 97, the speed of the child running opposite to the direction of motion of the belt isA. `4 km h^(-1)`B. `5 km h^(-1)`C. `9 km h^(-1)`D. `13 km h^(-1)` |
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Answer» Correct Answer - B In this case, `v_(BG) = 4 km h^(-1), v_(CB) = -9 km h^(-1)` `therefore` For an observer on a stationary platform, speed of child running opposite to the direction of motion of the belt is `v_(CG) = v_(CB) + v_(BG) = -9 km h^(-1) + 4 km h^(-1) = -5 km h^(_1)` -ve sign shows that the child appears to be moving from right to left with a speed of `5 km h^(-1)`. |
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