InterviewSolution
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InterviewSolution
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In the reaction `BrO^(-3)(aq) + 5Br^(-) (aq) + 6H^(+) rarr 3Br_(2)(1) + 3H_(2)O(1)` The rate of appearance of bromine `(Br_(2))` is related to rate of disapperance of bromide ions as folllwoing :A. `(d[Br_(2)])/(dt) = -(5)/(3) (d[Br^(-)])/(dt)`B. `(d[Br_(2)])/(dt)= (5)/(3) (d[Br^(-)])/(dt)`C. `(d[Br_(2)])= (3)/(5) (d[Br^(-)])/(dt)`D. `(d[Br_(2)])/(dt) = -(3)/(5) (d[Br^(-)])/(dt)` |
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Answer» Correct Answer - D For the reaction `BrO_(3)^(-)(aq)+5Br^(-)(aq)+6H^(+)(aq)rarr3Br_(2)(l)+3H_(2)O(l)` We have Rate `=-(d[BrO_(3)^(-)])/(dt)=-(d[Br^(-)])/(5dt)=-(d[H^(+)])/(6dt)` `=(d[Br_(2)])/(3dt)=-(d[H_(2)O])/(3dt)` Thus `(d[Br_(2)])/(dt)`=-(3)/(5)(d[Br^(-)])/(dt)` |
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