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In the reaction `BrO^(-3)(aq) + 5Br^(-) (aq) + 6H^(+) rarr 3Br_(2)(1) + 3H_(2)O(1)` The rate of appearance of bromine `(Br_(2))` is related to rate of disapperance of bromide ions as folllwoing : |
Answer» `BrO_(3)^(-)(aq)+5Br^(-)(aq) + 6H^(+) (aq) to 3Br_(2)(l) + 3H_(2)O(l)` `BrO_(3)^(-)(aq)+5Br^(-)(aq) + 6H^(+) (aq) to 3Br_(2)(l) + 3H_(2)O(l)` Rate of reaction in terms of `Br^(-)` ions and `Br_(2)` is: Rate (r) = `-1/5 (d[Br^(-)])/(dt) = 1/3 (d[Br_(2)])/(dt)` `(d[Br_(2)])/(dt) = -3/5(d[Br^(-)])/(dt)` |
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