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In the start of summer, a given sample of milk turns sour at room temperature `(27^(@)C)` in `48` hours. In a refrigerator at `2^(@)C`, milk can be stored there times longer before it sours. The time taken by the milk to sour at `37^(@)C`A. `35.2 hr`B. `32.5 hr`C. `35.3 hr`D. `32.3 hr` |
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Answer» Correct Answer - B Now `T_(1) = 300 K, T_(2) = 37^(@)C = 310 K` `E_(a) = 30146 J mol^(-1)` `log.(k_(310))/(k_(300)) = (30146 J mol^(-1))/(2.303 xx 8.314) xx (310 - 300)/(300 xx 310) = 0.1693` `:. (k_(310))/(k_(300)) = "antilog"(0.1693) = 1.477` Higher the rate constant, faster is the reaction, i.e., lesser is the time taken, hence `(t_(310))/(t_(300)) = (k_(300))/(k_(310)) = (1)/(1.477)` `:. t_(310) = t_(300) xx(1)/(1.477) = (48)/(1.477) = 32.5 hr` |
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