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InterviewSolution
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In the synthesis of ammonia by Haber process , if 60 moles of ammonia is obtained in one hour , then the rate of disapperance of Nitrogen isA. 30 mol/minB. 6 mol/minC. `0.5` mol/minD. 60 mol/min |
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Answer» Correct Answer - c `N_(2) + 3H_(2) = 2NH_(3)` rate = `- (d[N_(2)])/(dt) = -(1)/(3) (d[H_(2)])/(dt) = (1)/(2) (d[NH_(3)])/(dt)` Rate of disappearance of `N_(2)` `= (1)/(2)` of rate of formation of `NH_(3)` `= (1)/(2) xx (60 "mole")/(1"hour")= (1)/(2) xx (60)/(60)` mole/minute = 0.5 mole/minute . |
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